1. Dinalal divides his property among his four sons after donating Rs.20,000 and 10% of his remaining property. The amounts received by the last three sons are in arithmetic progression and the amount received by the fourth son is equal to the total amount donated. The first son receives as his share RS.20,000 more than the share of the second son. The last son received RS.1 lakh less than the eldest son. 10. Find the share of the third son. a) Rs.80,000 b) Rs.1,00,000 c) Rs.1,20,000 d) Rs.1,50,000 Ans: Assume the amounts received by the 2nd, 3rd, and 4th sons are a+d, a, a-d (as they are in AP) Now Eldest son received Rs.20,000 more than the 2nd son. So He gets a+d+20,000 Last son received 1 lakh less than the eldest son. So (a+d+20,000) - (a-d) = 1,00,000 ⇒ 2d = 80,000 ⇒ d = 40,000 So Amounts received by the 4 sons are a + 60,000, a+40,000, a, a - 40,000 It was given that the youngest son's share is equal to 20,000 + 1 2 (His ...
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